Re: Cirlcles within an specified area

Part of thread: Re: Cirlcles within an specified area · 0 replies ↳ In reply to Re: Cirlcles within an specified area — allen carpenter


Thanks Allen, this is gold for me.
Yes I agree that focal arrays may have other shapes than round, but it will just complicate the area further if we start to mess around with other geometrica shapes. even though we might not take it into account when designing.

More I look at a TLx50Mj limit, more certain I am about some inventor would build a work around. More arrays that fire at the same time at the same target. It then becomes a lasers equivalent of a shotgun. At short range the damage is tremendous, but as range increases the precission of the weapon drops and the converging beams starts to spread out.

At the moment I am not sure if I am going for a precission drop based on TL and range, or do it the easy way just base it on range alone. Deviation may be a either a fixed percentage of effect for each range band or a fraction of arrays that deviates at each range band.

--
Roger Malmstein
www.travellerfreeport.com

From: allen carpenter
Sent: Tuesday, October 27, 2009 1:01 AM
To:
Subject: Re: [Traveller_TNE] Re: Cirlcles within an specified area

oops
continued.
so if a bay is rectangular, why can't an entire end of the bay be the focal area when gravitic arrays are concerned?
if we assume handwavium for gravitic array focused beams, why stop there?

On Mon, Oct 26, 2009 at 7:58 PM, allen carpenter <> wrote:

ok, I will ask a seemingly simple (minded) question; Why do laser beam focal arrays have to be round, when they are graviticaly focused? Bays are assumed to be rectangular boxes based on common calculations (LXWXH)

On Mon, Oct 26, 2009 at 8:40 AM, atpollard <> wrote:

N = A / (R x R x 3.4641)

where:
N = Number that will Fit.
A = Area of Big circle or rectangle
R = Radius of a single array.

This treats the circular array as a hexagon (which will interlock) and divides the area (A) of the big circle-rectangle by the area of the Hexagon (R x R x 3.4641). The 3.4641 is derrived from [(Cotangent 30) x 2 x 6 / 2].

Enjoy.
Arthur

--- In , "Roger Malmstein" <starwolf@...> wrote:
>

> I would like to get some quick and dirty rule for how many circles of a
> specified radii I can get into either another circle or within a rectangular
> area.
> This request has something to do with my previous post about updating
> "Traveller Beam Factory". I have plans to enable laser turrets, barbettes
> and bays have more than one laser array if the array diameter is less than
> the diameter or width/length of the mount. It doesn't need to be precice as
> I have seen calculations for this and it just seizes up my brain. It can
> error on the side of fewer arrays as we can handwave it with a certain
> percent of the available area will be lost for technical purposes.
>

--
"Here at Ortillery Command we have at our disposal one hundred megawatt laser beams, mach 20 titanium rods and guided thermonuclear bombs. Some people say we think that we're God. We're not God. We just borrowed his SMITE button for our fire control system"

--
"Here at Ortillery Command we have at our disposal one hundred megawatt laser beams, mach 20 titanium rods and guided thermonuclear bombs. Some people say we think that we're God. We're not God. We just borrowed his SMITE button for our fire control system"