I was looking something up in TD19 and I caught the
following out of the corner of my eye. I don't know if it's of much use. Anyway,
someone wrote in asking what the proper way is to compute the seismic stress
factor if the subject world is a satellite of a gas giant.
Joe Fugate answered that one can generally ignore
the effects of the gas giant. Why? Because the gas giant's relatively low
density limits its impact to just a few diameters out. But if you want to be
sure, use the following formula.
M = (DxK) / (NxVx64)
M: Seismic effects of gas giant
D: Diameter of gas giant in km
K: Density of gas giant
N: Orbit number of world-moon in question
V: Orbit conversion factor (see below)
D: Diameter of gas giant in km
K: Density of gas giant
N: Orbit number of world-moon in question
V: Orbit conversion factor (see below)
V = gas giant diameter / world-moon diameter (both
in km)
When you plug in the numbers for Regina, you
get:
M = (240,000 x 0.27) / (55 x (240,000/11,200) x 64) = 0.86
M = (240,000 x 0.27) / (55 x (240,000/11,200) x 64) = 0.86
M < 1 you can ignore (according to
Joe).
If we put in Io...
N = Io's orbital radius / Jupiter's radius = 5.9
N = Io's orbital radius / Jupiter's radius = 5.9
M = (142,984 x 0.24) / (5.9 x (142,984/3,643) x 64)
= 2.3
So there's certainly more stress. While Jupiter is
smaller than Assiniboia (Regina's GG), Io is much closer than Regina is.
I make no guarantees of the veracity of this
formula (or my math). I'm just passing along the info. =)
\_/
DED
TNE @ Yahoo ml Admin